Question 633877
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Let *[tex \LARGE w] represent the width.  Then *[tex \LARGE w\ -\ 17] must represent the height.  Our good friend and constant companion, Pythagoras, says that the square of the diagonal is equal to the square of the width plus the square of the height:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ w^2\ -\ 34w\ +\ 289\ =\ 2809]


Collect terms and simplify:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ -\ 17w\ -\ 1260\ =\ 0]


Solve the factorable quadratic for *[tex \LARGE w], then calculate *[tex \LARGE w\ -\ 17]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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