Question 58151
 y-6 (over )y=5 2 (over)3b-3 (over)4=1(6b) 

4 (over) a+1=8 (over)2-a
:
{{{(y-6)/y = 5 }}}
Mult the eq by y, gets rid of the denominator and you have:
y - 6 = 5y
y - 5y = + 6
-4y = +6
  y = 6/-4
  y = -3/2
:
: 
{{{2/(3b) - 3/4 = 1/(6b)}}}
A good common denominator is 12b, mult eq by 12b and you have:
4(2) - 3b(3) = 2(1)
8 - 9b = 2
-9b = 2 - 8
-9b = -6
b = -6/-9
b = + 2/3
:
: 
{{{4/(a+1) = 8/(2-a)}}}
Since there is only one term on each side of equal sign, you can cross mult here
4(2-a) = 8(a+1)
8 - 4a = 8a + 8
-4a - 8a = 8 - 8
-12a = 0
a = 0
:
Check in the original equation, can see that a has to = 0: 4/1 = 8/2
:
It's a good idea to check the solutions in the 1st two problems by subtitution
in the original equations.