<PRE><B>Question 633787</B>
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If the perimeter is 10 more than twice the length, then 10 must be twice the width (refer to the formula for the perimeter of a rectangle), hence the width has to be 5.


If the width, which we now know to be 5 is 3 more than 1/4 of the length, 1/4 of the length has to be 2, hence the length is 4 times 2 or 8.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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