Question 633743
The diameters of peaches in a certain orchard are normally distributed with a mean of 4.01 inches and a standard deviation of 0.44 inches. Show all work.
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(A) What percentage of the peaches in this orchard is larger than 3.94 inches?
Find the z-value of 3.94
Find the probability of z being greater than that z-value.
Ans: 0.5632
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(B) A random sample of 100 peaches is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 3.94 inches?
z(3.94) = (3.94-4.01)/[0.44/sqrt(100)] = -1.5910
P(x-bar > 3.94) = P(z > -1.5910) = 0.9442
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Cheers,
Stan H.
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