Question 633383
Find an equation of the parabola that satisfies the given conditions.
Vertex V(-1, 0), focus F(-4, 0) 
This is a parabola that opens rightwards
Its standard form of equation: (y-k)^2=4p(x-h), (h,k)=coordinates of vertex
axis of symmetry: y=0 or x-axis
p=3 (-1 to -4) distance from vertex to focus on the axis of symmetry
4p=12
equation: y^2=12(x+1)