Question 633464
first we expand the second equation and we obtain {{{x^2+y^2-4y+4=1}}} and by substituting the first equation we get {{{9-4y+4=1}}} then {{{13-4y=1}}} then {{{-4y=-12}}} so {{{y=3}}} then we substitute in the first equation and we get {{{x^2+9=9}}} so {{{x=0}}}