Question 633540
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Find three consecutive even integers {{{highlight(x)}}}, {{{highlight(x+2)}}},{{{highlight(x + 4)}}} 
such that 3 times the sum of the first two is 48 less than the third
  3(2x+2) = (x+4) - 48
    5x = -50
     x = -10
Integers are -10, -8, -6

and...
{{{3*-18 = -54 = -6 - 48}}}