Question 633487
Im having difficulty with solving the following logarithim for X 
6^(2log base6 X + log base6 X) = 125 
**
6^(2log base6 X + log base6 X) = 125
place under single log
6^(log6[(x^2)x])=125
6^(log6[x^3])=125
base(6) raised to log of number(x^3)=number(x^3) (definition of logarithm)
x^3=125=5^3
x=5
..
Check: using calculator and change of base formula:
2log base6 X + log base6 X=2log base6(5) + log base6(5)≈2.694733
6^2.694733≈124.999954..