<PRE><B>Question 58127</B>
This system cannot be solved, as you will see, but here is the method
:
4x - 12y = 5
-x + 3y = -1
:
The easiest equation to use for substitution:
-x + 3y = -1
-x = -1 - 3y
x = (3y + 1); got rid of all those negatives, multiplied eq by -1
:
Substitute (3y + 1) for x in the 1st equation:
4x - 12y = 5
4(3y + 1) - 12y = 5
12y + 4 -12y = 5
12y - 12y = 5 - 4
       0 = 1
:
Obviously, this is not possible, so this system is inconsistant
:
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