Question 633452
<pre>
There are 4 aces out of 52 cards.  In probability "out of" means "over",
so

P(ace) = 4 out of 52 = 4 over 52 = {{{4/52}}} which reduces to {{{1/13}}}.


There is 1 four out of 6 numbers on the die. In probability "out of" means "over", so

P(four) = 1 out of 6 = 1 over 6 = {{{1/6}}}

We want to know

P(ace AND four).  In probability "AND" means "multiply", so

P(ace AND four) = P(ace)×P(four) = {{{1/13}}}×{{{1/6}}} = {{{1/78}}}

Edwin</pre>