Question 633467

16x^4+47x^2=3

16x^4 + 47x^2 - 3 = 0

(16x^2 -1)(x^2 + 3) = 0

16x^2 - 1 = 0;  x^2 + 3 = 0

16x^2 = 1;   x^2 = -3 (no solution, or radical 3*i, if using complex numbers)

x^2 = 1/16

x = +/- 1/4