Question 633339
It is impossible to answer the question without more information. At what angle does she hit the ball?<br>
If she hits the ball straight out (horizontally) then the initial velocity makes no difference. You just have to figure out how long it takes for the ball to drop 12 feet using the equation:
{{{-12 = -16t^2}}} (-12 for a drop of 12 and -16 is 1/2 the pull of gravity)<br>
If the ball is hit up or down at all, then you have to use Trig to figure out the vertical component (positive if she hits the ball upwards at some angle or negative if she hits it downward at all). Then use
{{{-12 = -16t^2 +v*t}}} (where "v" is the vertical component of the initial velocity)