Question 633328
Given the mean equal to 26 and the standard deviation equal to 3, what is the chance that a value of X greater than 18 will occur?
---------
z(18) = (18-26)/3 = -8/3
----
P(x > 18) = P(z > -8/3) = normalcdf(-8/3,100) = 0.9962
=============================
Cheers,
Stan H.