Question 633281
{{{(3x-4)^2=18}}} Start with the given equation.



{{{3x-4=""+-sqrt(18)}}} Take the square root of both sides.



{{{3x-4=sqrt(18)}}} or {{{3x-4=-sqrt(18)}}} Break up the "plus/minus" to form two equations.



{{{3x-4=3*sqrt(2)}}} or {{{3x-4=-3*sqrt(2)}}}  Simplify the square root.



{{{3x=4+3*sqrt(2)}}} or {{{3x=4-3*sqrt(2)}}} Add {{{4}}} to both sides.



{{{x=(4+3*sqrt(2))/3}}} or {{{x=(4-3*sqrt(2))/3}}} Divide both sides by 3 to completely isolate x.


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Answer:



So the solutions are {{{x=(4+3*sqrt(2))/3}}} or {{{x=(4-3*sqrt(2))/3}}}.


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