Question 633163
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Hi,
 58 students
25 are sophomores,   
34 are history majors
11 are neither.
 58-11 = 47
 59 - 47 =  12
12, both soph and history majors
13 sophmores only
22 history majors only
P(soph & H maj) = 12/58 = 6/29
P(soph, given H maj) =  {{{(12/58)/(22/58)}}} = 12/22 = 6/11  |P(A|B) = P(A and B)/P(B)