Question 633166
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
2y^2=6y-20
2y^2-6y = -20
2(y - 3/2)^2 -9/2  = -20 
2(y - 3/2)^2 =  -31/2
  (y-3/2)^2 = -31/4
     y = 3/2 ± isqrt(31)/2
Checking using Quadratic Formula     
2y^2-6y + 20 = 0
{{{y = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{y = (6 +- sqrt( -124 ))/(4) }}}
{{{y = 3/2 +- i*sqrt( 31)/2}}}