Question 632953
Complete the trinomial so it is a perfect square.   x^2 + ___+ 64 
Thanks a lot!


Since + 64 (c) is derived from {{{(b/2)^2}}}, then we can say that: {{{(b/2)^2 = 64}}}


{{{b^2/4 = 64}}}


{{{b^2 = 256}}} ------- Cross-multiplying


{{{b = sqrt(256)}}}, or {{{16}}}, making the middle term of the trinomial, {{{highlight_green(16x)}}}


The trinomial is therefore: {{{x^2 + 16x + 64}}}, or {{{(x + 8)^2}}}


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