Question 632893
The standard deviation of test scores on a certain achievement test is 11. A random sample of scores on this test had a mean of 70.5. Based on this sample, find a 90% confidence interval for the true mean of all scores. 
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x-bar = 70.5
ME = 1.645*[11/sqrt(n) = ?
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Question: What was the sample size?
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Cheers,
Stan H.
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Then complete the table below.
-what is the lower limit of the 90% confidence interval?
-what is the upper limit of the 90% confidence interval?