Question 632866
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Hi,
Note:  general Procedure is to first the eliminate one of the variables using a pair of EQs
{{{ 3x+5y-z=2 }}}  
{{{ -x-8y+3z=-6 }}}     |Multiplying 2nd Eq by 3 and adding to the first
     {{{y = (-8/7)x}}}
{{{ 3z=2x }}}  {{{z = (2/3)x}}}
{{{ 3x+5y-z=2 }}}      | Substituting for y and z 
    x =  -.5915
    y = {{{(-8/7)(-.5915) = .6761}}}
    z =  {{{(2/3)(-.5915) = -.3944}}}