Question 632814
Each even number has to end in {{{6}}}
since the other numbers are odd.
There are 4 choices for the 1st digit,
then there are 3 choices for the 2nd,
2 choices for the 3rd, 1 choice for the 4th,
So the number of possible even numbers
is {{{ 4*3*2*1 = 24 }}}