Question 58232
solve the quadratic equation by completing the square.

{{{2p^2=6p-20}}}
{{{2p^2=6p/2-20/2}}}  First divide everything by the coefficient of p^2
{{{p^2=3p-10}}}  The put the p^2 and p on one side and the constant on the other.
{{{p^2-3p=-10}}}
{{{p^2-3p+9/4=-10+9/4}}}  (1/2 the coefficient of p) suqred is added to both sides.
{{{(p-3/2)^2=-40/4+9/4}}}  Factor your perfect square, the second term is half the coefficient of p.
{{{(p-3/2)^2=-31/4}}}
{{{sqrt((p-3/2)^2)=+-sqrt(-31/4)}}}  take the square root of both sides
{{{p-3/2=+-sqrt(31)i/2}}}  The suqare root of -1 is i.
{{{p=3/2+-sqrt(31)i/2}}}
Happy Calculating!!!