Question 632570
In a survey of 1500 university students, 178 reported to be smokers. Test the sociologist claim that no more that 10% of university students are smokers. Use the 1% level of significance, and answer the following: 
Ho: p <= 0.10
Ha: p > 0.10
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p-hat = 178/1300 = 0.1369
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z(0.1369) = (0.1369-0.10)/sqrt(0.10*0.90/1300) = 4.7667
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P-Value = P(z> 4.7667) = normalcdf(0.7667,100) = 0.0000009373..
Cheers,
Stan H.