Question 632514
What is the equation of a line that passes through points (-1, 2) and (5, 2)?

(-1,2)

(5,2)

We must find the slope first.

(y2 - y1)/(x2 - x1)

(2 - 2)/(5 - (-1)

2 - 2 = 0

5 - (-1) = 5 + 1 = 6

0/6 = 0

The Slope (m) = 0

To find the equation of line we now use 

the point slope formula.

y - y1 = m(x - x1)

We take the coordinates (-1,2)

y - 2 = 0(x - (-1)

x - (-1) = x + 1

0(x + 1)

0 * x = 0x

0 * 1 = 0

Therefore:

y - 2 = 0x

Add 2 to each side of the equation.

y - 2 + 2 = 0x + 2

Combine like like terms:

-2 + 2 = 0

0x + 2 = 2

y = 2


y = 2 is a horizontal line. 

A horizontal line has zero slope.




Lennox Obuong
Algebra Student
Email: obuong3@aol.com