Question 632553
The rate at which the new robot works is {{{ x/1 }}} transmissions/hour
Old robot's rate = {{{ (x/8) / 1 }}}  transmissions/hour
Working together, just add the rates
Let {{{ k }}} = total transmissions produced
{{{ x/1 + x/8 = k/(5*24) }}}
{{{ x*( 1 + 1/8 ) = k / 120 }}}
{{{ k/120 = (9/8)*x  }}}
{{{ k = (( 9*120 )/8)*x }}}
{{{ k = 135x }}}
The new robot plus old robot can produce {{{ 135x }}} transmissions