Question 632535
find the slope, if it exists, of the line containing the pair of two points(-19,-16)(-20,-18)


We use the slope formula:

(y2 - y1)/(x2 - x1)

(-18 -(-16)/(-20 - (-19)

-18 -(-16) = -18 + 16 = -2

-20 -(-19) = -20 + 19 = -1

Therefore:

-2/-1 = 2

The Slope: 2


Now let's find out the equation of the line:


(y - y1) = m(x - x1)

y - (-16) = 2(x - (-19)

y - (-16) = y + 16

x - (-19) = x + 19

y + 16 = 2(x + 19)

2 * x = 2x

2 * 19 = 38

y + 16 = 2x + 38

Subtract 16 from each side of the equation.

y + 16 - 16 = 2x + 38 - 16

Combine like terms:

16 - 16 = 0

38 - 16 = 22

The equation of the line:

y = 2x + 22

The Slope: 2




Lennox Obuong
Algebra Student
obuong3@aol.com