Question 632437
Find the surface area of a cylinder with a base area of 49 π in2 and
 a height that is twice the radius of its base.
:
Find the radius from the given area of the base
{{{pi*r^2}}} = {{{49*pi}}}
divide both sides by {{{pi}}}
r^2 = 49
r = {{{sqrt(49)}}}
r = 7 inches is the radius
then
14 inches = the height
:
Surface area of a cylinder formula:
A = {{{2*pi*r^2}}} + {{{2*pi*r*h}}}
:
A = {{{2*pi*7^2}}} + {{{2*pi*7*14}}}
:
A = 307.876 + 615.752
:
A = 923.63 sq/inches