Question 632438
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In a word, no.


5 times 0 is 0, just like you said,

but look at the minus sign in front of the other 5.  That sign goes with the 5, not with the 5 + 3.  If there had been parentheses around the 5 + 3, as in:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9\ -\ (5\ +\ 5\ \cdot\ 0\ +3)\ =\ 1]


then you would have been correct, but:


9 minus 5 is 4


Then 


4 plus 3 is 7


And it really has nothing to do with going from left to right or vice versa, it is simply a matter of keeping the sign together with its term.


You could have finished the calculation thusly:


-5 plus 3 is -2


-2 plus 9 is 7


What might help you in the future would be to write everything as an addition problem.  Just forget that the operation of subtraction ever existed:


For this example, re-write thusly:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9\ +\ (-5)\ +\ 5\ \cdot\ 0\ +3]


Capisce?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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