Question 632354
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Hi,
Please carefully follow the work, so as you may learn how to others like it.
Solve the system of equations by using the inverse of the coefficient matrix.
x+8y=-29 
2x+3y=-19
{{{A = (matrix(2,2,a1,b1,a2,b2)) = a1b2-b1a2}}}                                  
{{{A =( matrix(2,2,1,8,2,3))}}} = -13
{{{A^(-1) = (1/(a1b2 - b1a2))(matrix(2,2,b2,-b1,-a2,a1))}}}
{{{A^(-1) = (-1/13)(matrix(2,2,3,-8,-2,1))= (matrix(2,2,-3/13,8/13,2/13,-1/13)) }}}

and...
{{{(matrix(2,1,x,y))= (matrix(2,2,-3/13,8/13,2/13,-1/13))(matrix(2,1,29,19))= (matrix(2,1,5,3)) }}}