Question 632314
-------------- 	percent	----------------	Amount										
Antifreeze I	20	----------------			100	gal							
Antifreeze II	60	----------------			x	gal							
Mixture	50	----------------	100	+	x	gal							
													
20	*	100	+	60	x	=	50	(	100	+	x	)	
2000	+	60	x	=	5000	+	50	x					
60	x		-50	x	=	-2000	+	5000					
10	x	=	3000										
/	10												
x	=	300		gal	Antifreeze II								
													
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