Question 632187

2n, 2n+2

(2n)(2n+2) = 9(2n+2n+2) - 18

4n^2 + 4n = 9(4n + 2) - 18

4n^2 + 4n = 36n + 18 - 18

4n^2 + 4n - 36n = 0

4n^2 - 32n = 0

4n(n - 8) = 0

n = 0, 8

two sets of consecutive even integers:

{0,2}

{16,18}

check:

16*18 = 9(16+18) - 18

288 = 9(34) - 18

288 = 306 - 18