Question 632158
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Hi,
3x &#8722; 5y + 2z = 2
 x &#8722; 3y + 2z = 2
5x &#8722; 11y + 6z = 6
Dependent system as D =0, as well as Dx=0, Dy= 0 and Dz = 0
or as demonstated by selecting different pairs of EQs and eliminating z for both: 
2x - 2y = 0
2x - 2y = 0    |Subtracting 2nd from 1st
     0 = 0   Dependent System
Dependent relationship in terms of z: (z-1, z-1, z)
 x = z - 1     |Eliminating y-variable using a pair of EQs
 y = z - 1     |Eliminating x-variable using a pair of EQs