Question 58197
2X^2+4=7X
2X^2-7X+4-0
USING THE QUADRATICK EQUATION WE GET
X=[(-(-7)+-SQRT(-7*-7-4*2*4)]/2*2
X=[7+-SQRT(49-32)]/4
X=[7+-SQRT17]/4
X=[7+-4.123]/4
X=11.123/4
X=2.78
X=2.877/4
X=.72