Question 632114
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Hi,
Find two consecutive integers{{{highlight(x)}}},  {{{highlight(x+1)}}}whose product is 72.
 x(x+1) = 72
 x^2 + x - 72 = 0
(x+9)(x-8) = 0 , x = -9  or x = 8
two consecutive integers are:  -9, -8   or  8, 9
There are no  two consecutive even integers whose product is 72

Find two consecutive even integers {{{highlight(x)}}}, {{{highlight(x+2)}}}whose product is 168. 
 x(x+2) = 168
 x^2 + 2x - 168 = 0 
(x+14)(x-12) = 0. x = -14   or x = 12
two consecutive even integers are:  -14, -12   or 12, 14