Question 7210
The discriminant would be the value of {{{ b^2 - 4ac }}} if the quadratic equation is written as {{{ ax^2 + bx + c = 0 }}}.


The equation above isn't quite yet in that form because the right side isn't 0. You'll have to move the terms to the left side and join them with their like terms by addition/subtraction. Once you do that, your equation should now look 


{{{ x^2 - 10x + 25 = 0 }}}


The a value would be the constant in front of the x^2 term. The b would be the constant in front of the x term, and c is the number standing by itself without variables attached to it. In this example, a = 1, b = -10, and c = 25.


Let's plug those into the b^2 - 4ac formula and see what we'll get:
(-10)^2 - 4*1*25 ---> 100 - 100 = 0. AHA! The discriminant turned out to be 0, which means that your quadratic equation has ONLY 1 solution.