Question 58198
Solve by completing the square

{{{x^2+2=2x}}}
{{{x^2-2x+2=0}}}
{{{x^2-2x+2-2=0-2}}}
{{{x^2-2x=-2}}}
{{{(x^2-2x+1)=-2+1}}}
{{{(x-1)^2=-1}}}
{{{sqrt((x-1)^2)=sqrt(-1)}}}
{{{x-1=+-i}}}
{{{x-1+1=1+-i}}}
x=1-i and x=1+i
If you are not using imaginary numbers yet, there is no solution.
Happy Calculating!!!