Question 631802
Log{subscript 8}x + log{subscript 8}(x-2)=2
log8(x)+log8(x-2)=2
log8[x(x-2)]=2
exponential form:
8^2=x(x-2)
x^2-2x=64
x^2-2x-64=0
use following quadratic formula to solve:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=-2, c=-64
ans:
x=-7.062 (reject, x>0)
or
x=9.062