Question 631852
The perimeter of a rectangle is {{{P=2(l+w)}}}
where {{{l}}} is the length, {{{w}}} is the width of a rectangle
Therefore
{{{(4x^2 +8x +18)=2(x^2 + 3x + 6+w)}}} divide by 2
{{{2x^2+4x+9=x^2+3x+6+w}}} Solve for {{{w}}}
{{{w=(2x^2+4x+9)-(x^2+3x+6)}}}
{{{w=2x^2+4x+9-x^2-3x-6}}}
{{{w=x^2+x+3}}}