<PRE><B>Question 631803</B>
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Center is at *[tex \LARGE (0,0)], Semi-major axis measures 5, semi-minor axis measures 2, so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(x\ -\ 0)^2}{4}\ +\ \frac{(y\ -\ 0)^2}{25}\ =\ 1]


Which reduces to:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x^2}{4}\ +\ \frac{y^2}{25}\ =\ 1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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