Question 631805
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Hi
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry
The standard form is {{{(x -h)^2 = 4p(y -k)}}}, where  the focus is (h,k + p)
and  length of  the  latus rectum 
directrix of  y= -3.25 and focus (0,-2.75), 
y-value of Midpoint between directrix and focus is -6/2 = -3 , p = .25  and 4p = 1  V(0,-3)
 {{{  x^2 = (y+3)}}}  or {{{y = x^2 - 3 }}}

 {{{drawing(300,300,   -6, 6, -6, 6,   grid(1),
circle(0, -3,0.3),
circle(0, -2.75,0.3),
graph( 300, 300, -6, 6, -6, 6,0,-3.25, x^2 - 3))}}}