Question 631790
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Hi,
three consecutive odd positive integers {{{highlight(x)}}}, {{{highlight(x + 2)}}} , {{{highlight(x+4)}}}
2 times the sum of all three is 9 less than the product of the first and second integers
  2(3x + 6)=x(x+2)-9
    6x + 12  = x^2 + 2x-9
           0 = x^2-4x - 21
           0 =  (x-7)(x+3)    x = 7 
The  three consecutive odd positive integers are 7 , 9 , 11

and...
  {{{2*27 = 54 = 7*9  - 9}}}