Question 631786
If X~Binomial(n,p) then mean of X = np and Variance of X = npq where q = 1-p.
Therefore, np = 3 and npq = 1.2
{{{npq/np = 1.2/3}}}
{{{q = 0.4}}}
{{{1-p = 0.4}}}
{{{highlight(p = 0.6)}}}
{{{np = 0.6n = 3}}}
{{{highlight(n = 5)}}}
{{{P(X<4) = (matrix(2,1,4,0))(0.6^0)(0.4^4) + (matrix(2,1,4,1))(0.6^1)(0.4^3) + (matrix(2,1,4,2))(0.6^2)(0.4^2) + (matrix(2,1,4,3))(0.6^3)(0.4^1)}}}
{{{highlight(P(X<4) = 0.663)}}}