Question 631600
(3,4) and (-2,5)
The equation for this line is to be determined.
x1		y1	x2	y2				
3		4	-2	5				
								
slope m =		(y2-y1)/(x2-x1)						
(	5	-	4	)/(	-2	-	3	)
(	1	/	-5	)  				
m=		-  1/ 5						 
								
Find theco-ordinates of the mid point (3,4) and (-2,5)


(3-2)/2 = 0.5

(4+5)/2 = 4.5

The co-ordinates of the mid point are (0.5,4.5)

Equation of line perpendicular to the line joining (3,4) and (-2,5)and passing through (0.5,4.5) 
Equation of line joining the points 
y  	=	-  1/ 5	x	+	23/5				
Divide by	1									
	y  	=	-  1/ 5	x	+	23/5				
Compare this equation with y=mx+b,	
m= slope & b= y intercept					
slope m =	- 1/5									
										
The slope of a line perpendicular to the above line will be the negative reciprocal.										    
Because m1*m2 =-1										
The slope of the required line will be	5    							
										
m=	5    	,point	(	0.5	,	4.5	)			
Find b by plugging the values of m & the point in										
y=mx+b										
4.5	=	5/ 2	+	b						
b=	2    									
m=	5    									
The required equation is	y=5x+2      	

m.ananth@hotmail.ca