Question 631545
<pre>
{{{2^(x + 4)}}} = {{{5^(x - 3)}}}

{{{log((2^(x + 4)))}}} = {{{log((5^(x - 3)))}}}

(x+4)log(2) = (x-3)log(5)

Let log(2) = A and log(5) = B

(x+4)A = (x-3)B

A(x+4) = B(x-3)

Ax+4A = Bx-3B

Ax-Bx = -4A-3B

x(A-B) = -4A-3B

x = {{{(-4A-3B)/(A-B)}}}

x = {{{(-4log((2))-3log((5)))/(log((2))-log((5)))}}}

Get your calculator. 

x = 8.295295582 rounds to 8.2953

Edwin</pre>