Question 631474
You know, {{{i^2=-1}}}
{{{(11i^2+1)/(-12i-8)=-(-11+1)/(12i+8)=10/(12i+8)}}}
Multiply numerator and denominator by {{{(12i-8)}}}
{{{10/(12i+8)=10(12i-8)/((12i+8)(12i-8))=(120i-80)/(144i^2-64)=(120i-80)/(-144-64)=(120i-80)/(-208)=-120/208+(80/208)i=-15/26+(5/13)i}}}