Question 631464
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Hi,
the diagonal of a rectangle is 15 cm. long. 
 length is 3 cm. longer than its width {{{highlight(x)}}}
Question states*** 
appying the Pythagorean Theorem
 x^2 + (x+3)^2 = 225
 x^2 + x^2 + 6x + 9 = 225
 x^2 + 3x - 108 = 0
factoring
 (x +12)(x-9) = 0
       x = 9cm, its width (throwing out negative solution for unit measure)
              length = 12cm  {{{9+3}}}
 P = 2*9cm + 2*12cm = 42cm