Question 631281
How many mL of acid must be added to 50 mL of a 10% acid solution in order to produce a 20% acid solution?
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let x=amt of acid to add
10%*50+100%x=20%(50+x)
5+x=10+.2x
.8x=5
x=6.25
amt of acid to add=6.25 mL