Question 631107
Let x be the length of the side of the cube, in meters.
The volume of the cube (in cubic meters) is {{{x^3=4096}}}.
It so happens that 4096 is a perfect cube.
{{{4096=2^12=(2^4)63=16^3}}}
{{{x^3=4096}}} --> {{{x=root(3,4096)}}} --> {{{x=16}}}
The surface area of one face of the cube (in square meters) is
{{{x^2=16^2=256}}}
The surface area of all six faces of the cube  (in square meters) is
{{{6*256}}}
The number of cans of paint needed, if each can will cover 60 square meters is
{{{6*250/60=25.6}}}
The artist will have to buy {{{highlight(26)}}} cans of paint.