Question 631267
={{{6/(a+2)-1/(a-3)}}}
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={{{(6(a-3)-1(a+2))/(a+2)(a-3)}}}
={{{(6a-18-a-2)/(a+2)(a-3)}}}
={{{(5a-20)/(a+2)(a-3)}}}
={{{5(a-4)/(a+2)(a-3)}}}