Question 629291
2n+1, 2n+3, 2n+5

(2n+1)(2n+3) - 6(2n+5) = 21

4n^2 + 8n + 3 - 12n - 30 = 21

4n^2 -4n -27 -21 = 0

4n^2 - 4n - 48 = 0

n^2 - n - 12 = 0

(n+3)(n-4) = 0

n = -3, 4

two sets of numbers satisfy: 

{-5, -3, -1}
{9, 11, 13}