Question 631205
{{{w/x+y/z}}}



{{{(w/x)(z/z)+(y/z)(x/x)}}}



{{{(wz)/(xz)+(yx)/(xz)}}}



{{{(wz+yx)/(xz)}}}



{{{(wz+xy)/(xz)}}}



So the answer is {{{(wz+xy)/(xz)}}}


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